Optimal. Leaf size=137 \[ -\frac{i a b d \text{PolyLog}\left (2,e^{2 i (e+f x)}\right )}{f^2}+\frac{a^2 (c+d x)^2}{2 d}+\frac{2 a b (c+d x) \log \left (1-e^{2 i (e+f x)}\right )}{f}-\frac{i a b (c+d x)^2}{d}-\frac{b^2 (c+d x) \cot (e+f x)}{f}-b^2 c x+\frac{b^2 d \log (\sin (e+f x))}{f^2}-\frac{1}{2} b^2 d x^2 \]
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Rubi [A] time = 0.174217, antiderivative size = 137, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 7, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.389, Rules used = {3722, 3717, 2190, 2279, 2391, 3720, 3475} \[ -\frac{i a b d \text{PolyLog}\left (2,e^{2 i (e+f x)}\right )}{f^2}+\frac{a^2 (c+d x)^2}{2 d}+\frac{2 a b (c+d x) \log \left (1-e^{2 i (e+f x)}\right )}{f}-\frac{i a b (c+d x)^2}{d}-\frac{b^2 (c+d x) \cot (e+f x)}{f}-b^2 c x+\frac{b^2 d \log (\sin (e+f x))}{f^2}-\frac{1}{2} b^2 d x^2 \]
Antiderivative was successfully verified.
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Rule 3722
Rule 3717
Rule 2190
Rule 2279
Rule 2391
Rule 3720
Rule 3475
Rubi steps
\begin{align*} \int (c+d x) (a+b \cot (e+f x))^2 \, dx &=\int \left (a^2 (c+d x)+2 a b (c+d x) \cot (e+f x)+b^2 (c+d x) \cot ^2(e+f x)\right ) \, dx\\ &=\frac{a^2 (c+d x)^2}{2 d}+(2 a b) \int (c+d x) \cot (e+f x) \, dx+b^2 \int (c+d x) \cot ^2(e+f x) \, dx\\ &=\frac{a^2 (c+d x)^2}{2 d}-\frac{i a b (c+d x)^2}{d}-\frac{b^2 (c+d x) \cot (e+f x)}{f}-(4 i a b) \int \frac{e^{2 i (e+f x)} (c+d x)}{1-e^{2 i (e+f x)}} \, dx-b^2 \int (c+d x) \, dx+\frac{\left (b^2 d\right ) \int \cot (e+f x) \, dx}{f}\\ &=-b^2 c x-\frac{1}{2} b^2 d x^2+\frac{a^2 (c+d x)^2}{2 d}-\frac{i a b (c+d x)^2}{d}-\frac{b^2 (c+d x) \cot (e+f x)}{f}+\frac{2 a b (c+d x) \log \left (1-e^{2 i (e+f x)}\right )}{f}+\frac{b^2 d \log (\sin (e+f x))}{f^2}-\frac{(2 a b d) \int \log \left (1-e^{2 i (e+f x)}\right ) \, dx}{f}\\ &=-b^2 c x-\frac{1}{2} b^2 d x^2+\frac{a^2 (c+d x)^2}{2 d}-\frac{i a b (c+d x)^2}{d}-\frac{b^2 (c+d x) \cot (e+f x)}{f}+\frac{2 a b (c+d x) \log \left (1-e^{2 i (e+f x)}\right )}{f}+\frac{b^2 d \log (\sin (e+f x))}{f^2}+\frac{(i a b d) \operatorname{Subst}\left (\int \frac{\log (1-x)}{x} \, dx,x,e^{2 i (e+f x)}\right )}{f^2}\\ &=-b^2 c x-\frac{1}{2} b^2 d x^2+\frac{a^2 (c+d x)^2}{2 d}-\frac{i a b (c+d x)^2}{d}-\frac{b^2 (c+d x) \cot (e+f x)}{f}+\frac{2 a b (c+d x) \log \left (1-e^{2 i (e+f x)}\right )}{f}+\frac{b^2 d \log (\sin (e+f x))}{f^2}-\frac{i a b d \text{Li}_2\left (e^{2 i (e+f x)}\right )}{f^2}\\ \end{align*}
Mathematica [A] time = 2.16488, size = 200, normalized size = 1.46 \[ \frac{\sin (e+f x) (a+b \cot (e+f x))^2 \left (-2 i a b d \sin (e+f x) \text{PolyLog}\left (2,e^{2 i (e+f x)}\right )+\sin (e+f x) \left (-(e+f x) \left (a^2 (-2 c f+d e-d f x)+2 i a b d (e+f x)+b^2 (2 c f-d e+d f x)\right )+2 b \log (\sin (e+f x)) (2 a c f-2 a d e+b d)+4 a b d (e+f x) \log \left (1-e^{2 i (e+f x)}\right )\right )-2 b^2 f (c+d x) \cos (e+f x)\right )}{2 f^2 (a \sin (e+f x)+b \cos (e+f x))^2} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.36, size = 365, normalized size = 2.7 \begin{align*} 2\,iabcx-{\frac{4\,ibadex}{f}}+{\frac{{a}^{2}d{x}^{2}}{2}}-{\frac{{b}^{2}d{x}^{2}}{2}}+{a}^{2}cx-{b}^{2}cx-{\frac{2\,iabd{\it polylog} \left ( 2,-{{\rm e}^{i \left ( fx+e \right ) }} \right ) }{{f}^{2}}}+{\frac{{b}^{2}d\ln \left ({{\rm e}^{i \left ( fx+e \right ) }}+1 \right ) }{{f}^{2}}}-2\,{\frac{{b}^{2}d\ln \left ({{\rm e}^{i \left ( fx+e \right ) }} \right ) }{{f}^{2}}}+{\frac{{b}^{2}d\ln \left ({{\rm e}^{i \left ( fx+e \right ) }}-1 \right ) }{{f}^{2}}}+2\,{\frac{abc\ln \left ({{\rm e}^{i \left ( fx+e \right ) }}-1 \right ) }{f}}+2\,{\frac{abc\ln \left ({{\rm e}^{i \left ( fx+e \right ) }}+1 \right ) }{f}}-4\,{\frac{abc\ln \left ({{\rm e}^{i \left ( fx+e \right ) }} \right ) }{f}}-2\,{\frac{abde\ln \left ({{\rm e}^{i \left ( fx+e \right ) }}-1 \right ) }{{f}^{2}}}+4\,{\frac{abde\ln \left ({{\rm e}^{i \left ( fx+e \right ) }} \right ) }{{f}^{2}}}-{\frac{2\,iabd{\it polylog} \left ( 2,{{\rm e}^{i \left ( fx+e \right ) }} \right ) }{{f}^{2}}}-{\frac{2\,iabd{e}^{2}}{{f}^{2}}}-iabd{x}^{2}+2\,{\frac{b\ln \left ({{\rm e}^{i \left ( fx+e \right ) }}+1 \right ) adx}{f}}+2\,{\frac{b\ln \left ( 1-{{\rm e}^{i \left ( fx+e \right ) }} \right ) adx}{f}}+2\,{\frac{b\ln \left ( 1-{{\rm e}^{i \left ( fx+e \right ) }} \right ) ade}{{f}^{2}}}-{\frac{2\,i{b}^{2} \left ( dx+c \right ) }{f \left ({{\rm e}^{2\,i \left ( fx+e \right ) }}-1 \right ) }} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.79219, size = 1046, normalized size = 7.64 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.92315, size = 957, normalized size = 6.99 \begin{align*} -\frac{2 \, b^{2} d f x + i \, a b d{\rm Li}_2\left (\cos \left (2 \, f x + 2 \, e\right ) + i \, \sin \left (2 \, f x + 2 \, e\right )\right ) \sin \left (2 \, f x + 2 \, e\right ) - i \, a b d{\rm Li}_2\left (\cos \left (2 \, f x + 2 \, e\right ) - i \, \sin \left (2 \, f x + 2 \, e\right )\right ) \sin \left (2 \, f x + 2 \, e\right ) + 2 \, b^{2} c f +{\left (2 \, a b d e - 2 \, a b c f - b^{2} d\right )} \log \left (-\frac{1}{2} \, \cos \left (2 \, f x + 2 \, e\right ) + \frac{1}{2} i \, \sin \left (2 \, f x + 2 \, e\right ) + \frac{1}{2}\right ) \sin \left (2 \, f x + 2 \, e\right ) +{\left (2 \, a b d e - 2 \, a b c f - b^{2} d\right )} \log \left (-\frac{1}{2} \, \cos \left (2 \, f x + 2 \, e\right ) - \frac{1}{2} i \, \sin \left (2 \, f x + 2 \, e\right ) + \frac{1}{2}\right ) \sin \left (2 \, f x + 2 \, e\right ) - 2 \,{\left (a b d f x + a b d e\right )} \log \left (-\cos \left (2 \, f x + 2 \, e\right ) + i \, \sin \left (2 \, f x + 2 \, e\right ) + 1\right ) \sin \left (2 \, f x + 2 \, e\right ) - 2 \,{\left (a b d f x + a b d e\right )} \log \left (-\cos \left (2 \, f x + 2 \, e\right ) - i \, \sin \left (2 \, f x + 2 \, e\right ) + 1\right ) \sin \left (2 \, f x + 2 \, e\right ) + 2 \,{\left (b^{2} d f x + b^{2} c f\right )} \cos \left (2 \, f x + 2 \, e\right ) -{\left ({\left (a^{2} - b^{2}\right )} d f^{2} x^{2} + 2 \,{\left (a^{2} - b^{2}\right )} c f^{2} x\right )} \sin \left (2 \, f x + 2 \, e\right )}{2 \, f^{2} \sin \left (2 \, f x + 2 \, e\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (a + b \cot{\left (e + f x \right )}\right )^{2} \left (c + d x\right )\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (d x + c\right )}{\left (b \cot \left (f x + e\right ) + a\right )}^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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